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IPv4 Address Conversion: Binary to Decimal and Decimal to Binary Complete Guide

Content Introduction

This tutorial provides step-by-step methods for converting IPv4 addresses between binary and dotted decimal notation using the 8-bit place value system (128, 64, 32, 16, 8, 4, 2, 1), with detailed examples and practice problems for mastering IP address conversion techniques.

Key Information

  • 1IPv4 addresses use 32 bits organized into four 8-bit octets
  • 2Binary to decimal conversion: Sum place values where bits are 1
  • 3Decimal to binary conversion: Subtract largest possible place values
  • 48-bit place values: 128, 64, 32, 16, 8, 4, 2, 1 (2^7 to 2^0)
  • 5Each octet must convert to decimal between 0-255
  • 6Conversion follows consistent mathematical patterns

Content Keywords

#Binary to Decimal Conversion

Process of converting 8-bit binary octets to decimal by summing place values where bits are set to 1

#Decimal to Binary Conversion

Process of converting decimal numbers to 8-bit binary by subtracting largest possible place values

#8-bit Place Values

Fixed values 128, 64, 32, 16, 8, 4, 2, 1 used for binary-decimal conversion calculations

#Octet Conversion

Individual conversion of each 8-bit section in IPv4 address between binary and decimal formats

#IPv4 Address Structure

32-bit address divided into four 8-bit octets for network device identification

#Place Value Method

Systematic approach using fixed place values for accurate binary-decimal conversions

Related Questions and Answers

Q1.How do you convert binary 10010001 to decimal?

A: Identify bits set to 1: positions 128 and 1. Sum: 128 + 1 = 129. Result: 129

Q2.What is the process for converting decimal 145 to binary?

A: Subtract largest possible values: 145-128=17, 17-16=1, 1-1=0. Set bits at 128, 16, 1. Result: 10010001

Q3.Why are the place values 128, 64, 32, 16, 8, 4, 2, 1 used?

A: These represent 2^7 to 2^0, covering all possible values in an 8-bit binary number (0-255)

Q4.How do you handle conversion when all bits are 1?

A: All bits 1 = 128+64+32+16+8+4+2+1 = 255. This is the maximum value for one octet

Q5.What is the binary equivalent of decimal 14?

A: 14 = 8+4+2. Set bits at positions 8, 4, 2. Result: 00001110

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